dint get da question properly here n assumin dere iz friction ,,,,, whr r u movin da block upward or downward along da sheet..ie in da first case at an angle x
w=kmgd in paralled to da grnd,,, k=coff. of friction d=distance travelled in incline; w=(kmgcosx)d+(mgdsinx) =mgd(kcosx+sinx); because one iz wrk against friction n othr inc. in potential energy........ n here diff values of k n x will yield diff results,,,,n above results r assuming dat block moved wid a velocity->0..
Nice answer expected this from you.A correct approach to start. actually in the first case the work to increase potential is 0 but the whole work is done against the friction while in the second case the work is done against both friction and potential but the work done due to friction is low as compared to the previous so we cant always comment that moving a block up the plane is more energy consuming as we increase the value of k and x the result tends to be low in the second case
dont under estimate the question
ReplyDeletedint get da question properly here
ReplyDeleten assumin dere iz friction ,,,,, whr r u movin da block upward or downward along da sheet..ie in da first case at an angle x
moving the block upward
ReplyDeletew=kmgd in paralled to da grnd,,,
ReplyDeletek=coff. of friction
d=distance travelled
in incline;
w=(kmgcosx)d+(mgdsinx)
=mgd(kcosx+sinx);
because one iz wrk against friction n othr inc. in potential energy........
n here diff values of k n x will yield diff results,,,,n above results r assuming dat block moved wid a velocity->0..
Nice answer expected this from you.A correct approach to start. actually in the first case the work to increase potential is 0 but the whole work is done against the friction while in the second case the work is done against both friction and potential but the work done due to friction is low as compared to the previous so we cant always comment that moving a block up the plane is more energy consuming as we increase the value of k and x the result tends to be low in the second case
ReplyDelete